If Z is the centroid of triangle TUV, TZ=60, XZ=28, and WZ=25, find each missing measure

(Quick please ) !!!!!!!!!!!!!!!! Help me!!!!! find the surface area of the rectangular prism!!!!!! thank you

Aleks [24]

You can do this !

The rectangular prism has

   -- length = 10 cm
   -- width = 7 cm
   -- height = 3 cm.

-- The area of the top and bottom is (length x width) each.

-- The area of the left and right sides is (length x height) each.

-- The area of the front and back is (width x height) each.

There. I just laid out all the schmartz you need to answer this question.
The rest is all simple arithmetic, and you're perfectly capable of turning
the crank and getting the answer. You don't need anybody else to do
that part for you.

Don't forget your units. The area of each flat face is (cm) times (cm),
and that product will be some cm² , for area.

3 0

3 years ago

Solve the system of linear equations by graphing <br> y=1/3x+5<br> y=2/3x+5<br> What is the solution

Tamiku [17]

Answer:

We have the system of equations:

y=1/3x+5

y=2/3x+5

To solve it graphically, we need to graph both lines and see in which point the lines intersect.

You can see the graph below, and you can see that the lines intersect in the point (0, 5)

Now, we can also solve this analytically.

We can use the fact that for the solution, we need y = y.

Then we can write:

(1/3)*x + 5 = (2/3)*x + 5

First, we can subtract 5 in both equations to get:

(1/3)*x = (2/3)*x

This only has a solution when x = 0.

Replacing x = 0 in one of the equations, we get:

y = (1/3)*0 + 5 = 5

Then the solution is x = 0, and y = 5, as we already could see in the graph.

3 0

2 years ago

According to the graph, what is the experimental probability of selecting the letter E?

Daniel [21]

The experimental probability of letter E is: 3/25

Step-by-step explanation:

The given diagram is the number of outcomes for each letter is given

We have to find the total number of outcomes for finding the experimental probability of letter E

So,

Total outcomes = n(S) = 5+12+8+10+6+9 = 50

Number of outcomes for Letter E = n(E) = 6

So the experimental probability will be:

$P(E) = \frac{n(E)}{n(S)}\\\\=\frac{6}{50}\\\\= \frac{3}{25}$

Hence,

The experimental probability of letter E is: 3/25

Keywords: Probability, experimental probability

Learn more about probability at:

#LearnwithBrainly

7 0

2 years ago

A jet is flying 7 miles above the ground. The pilot spots an airport as shown below. What is the distance from the plane to the

Fynjy0 [20]

It's hard to help if you can't provide everything with the question

8 0

3 years ago

Select ALL the correct answers.

Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0

2 years ago