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Sveta_85 [38]
3 years ago
13

Use the Counting Principle to find the probability of choosing the 6 winning lottery numbers when the numbers are chosen at rand

om from 0 to 9.
Mathematics
2 answers:
kramer3 years ago
5 0

Answer: 210

<u>Step-by-step explanation:</u>

choose 6 numbers out of 10:

₁₀C₆ = \frac{10!}{(10-6)!(6)!}

       = \frac{10*9*8*7*6!}{(4)!(6)!}

       = \frac{10*9*8*7}{(4)!}

       = \frac{10*9*8*7}{4*3*2}

       = 10 * 3 * 7

        = 210


jek_recluse [69]3 years ago
4 0

Answer:

How many ways can 6 numbers be chosen from 10?

combinations = n! / r! *(n-r)!

combinations = 10! / (6! * 4!)

combinations = 10 * 9 * 8 * 7 * 6! / (6! * 4!)

combinations = 10 * 9 * 8 * 7 / 4 * 3 * 2* 1

combinations = 10 * 3 * 7

combinations = 210

So the probability is 1 / 210 or 0.0047619048



Step-by-step explanation:


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What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?
Trava [24]

Answer:

\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}

Step-by-step explanation:

The explicit formula for a geometric sequence:

a_n=a_1r^{n-1}

a_n - n-th term

a_1 - first term

r - common ratio

r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}

We have

a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...

The common ratio:

r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}

<h2>It's not a geometric sequence.</h2>

If a_3=-\dfrac{1}{16} then the common ratio is r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}

Put to the explicit formula:

a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}

Put a_n=\dfrac{1}{1024} and solve for <em>n </em>:

-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1

\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6

5 0
3 years ago
Is
elena55 [62]

Answer:

C. 0.300 s.

53

11 + x

Step-by-step explanation:

brainest plz

4 0
3 years ago
Read 2 more answers
Need help ASAP !!!!<br> Solve for the missing side. Round answer to two decimal places (like 7.93).
Thepotemich [5.8K]
10.44yd
a^2 + b^2 = c^2
3^2 + 10^2 = c^2
109 = c^2
C (Hypotenuse) ≈ 10.44
3 0
3 years ago
A coin is to be tossed until a head appears twice in a row. What is the sample space for this experiment? If the coin is fair, w
blsea [12.9K]

Answer:

The sample space would be infinite

{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}

1/8

Step-by-step explanation:

The sample space would be infinite

{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}.

This is because the number of times the coin would be flipped is not specified. So, you can keep flipping the coin forever.

If the coin is tossed four times then the sample space would be

{HHHH HTHH THHH HTHT

HHHT HTTH TTHH THTH

HHTT HHTH TTTH THHT

HTTT TTTT TTHT THTT}

HTHH and TTHH are the only two cases where two consecutive tosses will result in two heads

Probability that the coin will be tossed four times is 2/16 = 1/8

6 0
3 years ago
What is the degress for a half of of circle if it cut in 1/3
11111nata11111 [884]
Half of a circle

1 circle=360
1/2 circle=360/2=180

1/2 circle cut into 1/3
180 times 1/3=60
60 degreees
6 0
3 years ago
Read 2 more answers
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