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Sveta_85 [38]
3 years ago
13

Use the Counting Principle to find the probability of choosing the 6 winning lottery numbers when the numbers are chosen at rand

om from 0 to 9.
Mathematics
2 answers:
kramer3 years ago
5 0

Answer: 210

<u>Step-by-step explanation:</u>

choose 6 numbers out of 10:

₁₀C₆ = \frac{10!}{(10-6)!(6)!}

       = \frac{10*9*8*7*6!}{(4)!(6)!}

       = \frac{10*9*8*7}{(4)!}

       = \frac{10*9*8*7}{4*3*2}

       = 10 * 3 * 7

        = 210


jek_recluse [69]3 years ago
4 0

Answer:

How many ways can 6 numbers be chosen from 10?

combinations = n! / r! *(n-r)!

combinations = 10! / (6! * 4!)

combinations = 10 * 9 * 8 * 7 * 6! / (6! * 4!)

combinations = 10 * 9 * 8 * 7 / 4 * 3 * 2* 1

combinations = 10 * 3 * 7

combinations = 210

So the probability is 1 / 210 or 0.0047619048



Step-by-step explanation:


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Step-by-step explanation:

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Let’s solve the equation for w:

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Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

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In which

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  • P(A \cap B) is the probability of both A and B happening.
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In this problem:

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A similar problem is given at brainly.com/question/14398287

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