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Sveta_85 [38]
3 years ago
13

Use the Counting Principle to find the probability of choosing the 6 winning lottery numbers when the numbers are chosen at rand

om from 0 to 9.
Mathematics
2 answers:
kramer3 years ago
5 0

Answer: 210

<u>Step-by-step explanation:</u>

choose 6 numbers out of 10:

₁₀C₆ = \frac{10!}{(10-6)!(6)!}

       = \frac{10*9*8*7*6!}{(4)!(6)!}

       = \frac{10*9*8*7}{(4)!}

       = \frac{10*9*8*7}{4*3*2}

       = 10 * 3 * 7

        = 210


jek_recluse [69]3 years ago
4 0

Answer:

How many ways can 6 numbers be chosen from 10?

combinations = n! / r! *(n-r)!

combinations = 10! / (6! * 4!)

combinations = 10 * 9 * 8 * 7 * 6! / (6! * 4!)

combinations = 10 * 9 * 8 * 7 / 4 * 3 * 2* 1

combinations = 10 * 3 * 7

combinations = 210

So the probability is 1 / 210 or 0.0047619048



Step-by-step explanation:


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Answer:

54

Step-by-step explanation:

162/3 = 54

3 0
2 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
PLEASE HELP NOW --- &gt;N is a 2-digit even number. If the last two digits of N^2 is the same as N, what is the sum of digits of
taurus [48]

Answer:

76.

Step-by-step explanation:

It is given that N is a 2-digit number.

Last two digits of N^2 is the same as N.

We know that, a number is even if it ends with 0,2,4,6,8.

2^2=4,4^2=16,6^2=36,8^2=64

If 0 is in end then we get two zeros in the square of that number.

It is clear that, number should ends with 6 to get the same number at the end.

16^2=256

26^2=676

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46^2=2116

56^2=3136

66^2=4356

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86^2=7396

96^2=9216

It is clear that last two digits of (76)^2 is the same as 76.

Therefore, the required number is 76.

6 0
3 years ago
Find the mean:<br> 8, 10, 10, 10, 6, 7, 8
Delicious77 [7]

Answer:

8.43

Step-by-step explanation:

8 + 10 + 10 + 10 + 6 + 7 + 8 = 59

59/7 = 8.43 (or keep as improper fraction)

8 0
3 years ago
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vesna_86 [32]
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3 years ago
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