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beks73 [17]
3 years ago
7

If a tree 28 meters tall casts a shadow 32 meters long, what is the angle of elevation of the sun to the nearest degree?

Mathematics
2 answers:
blagie [28]3 years ago
7 0
We need an angle measure we have to use an inverse trig ratio, sin^-1, cos^-1, or tan^-1.
Setting up the right triangle we have the opposite and adjacent so we use tan.
tan angle = 28/32
tan^-1 (28/32) = 41 degrees
zysi [14]3 years ago
4 0
Height = 28m
shadow = 32

Angle = tan^-1 (28/32) = 41.18 degree

Hope it helps!
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The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chaneece choo
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Answer:

The value of x lies between 20 and 40 and value of y lies between -20 and 10

Step-by-step explanation:

We are given that

y\leq 40-x....(1)

y\leq x-20...(2)

First we convert inequality equation into equality equation to find the solution of the given system of inequality equation.

Therefore, we can write as

y=-x+40...(3)

y=x-20...(4)

Adding equation (3) and (4) we get

2y=20

y=10

Substitute y=10 in equation (3) we get

10=40-x

x=40-10=30

(30,10) is the intersect point of two equation.

Put x=0 in equation (3)

y=40

Substitute y=0 in equation (3)

x=40

Substitute x=0 in equation (4)

y=-20

Substitute y=0 in equation (4)

x=20

Substitute x=0 and y=40 and in equation (1)

40\leq 40

Hence, the equation is true.Therefore, the shaded region below the line.

Substitute x=0 and y=-20 in equation (2)

-20\leq -20

The equation is true. Hence, the shaded region is below the line.

Hence, the value of x lies between 20 and 40 and value of y lies between -20 and 10.

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show that thw roots of the equation (x-a)(x_b)=k^2 are always real if a,b and k are real. Please I really need help with this
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Answer:

see explanation

Step-by-step explanation:

Check the value of the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real

• If b² - 4ac = 0 roots are real and equal

• If b² - 4ac < 0 then roots are not real

given (x - a)(x - b) = k² ( expand factors )

x² - bx - ax - k² = 0 ( in standard form )

x² + x(- a - b) - k² = 0

with a = 1, b = (- a - b), c = -k²

b² - 4ac = (- a - b)² + 4k²

For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0

Hence roots of the equation are always real for a, b, k ∈ R


           

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