Answer:
About anything that adds up to 90...
Step-by-step explanation:
Answer:
150 feet by 300 feet.
Step-by-step explanation:
The fence is to enclose a rectangular area of 45,000 ft squared.
If the dimensions of the rectangle are x and y
Area of a rectangle = xy
- xy=45000
![x=\frac{45000}{y}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B45000%7D%7By%7D)
Perimeter of the Rectangle =2x+2y
Fencing material costs $ 3 per foot for the two sides facing north and south and $6 per foot for the other two sides.
- Cost of Fencing, C=$(6*2x+3*2y)=$(12x+6y)
Substitute
into the Cost to get C(y)
C=12x+6y
![C(y)=12(\frac{45000}{y})+6y\\C(y)=\frac{540000+6y^2}{y}](https://tex.z-dn.net/?f=C%28y%29%3D12%28%5Cfrac%7B45000%7D%7By%7D%29%2B6y%5C%5CC%28y%29%3D%5Cfrac%7B540000%2B6y%5E2%7D%7By%7D)
The value at which the cost is least expensive is at the minimum point of C(y), when the derivative is zero.
![C^{'}(y)=\dfrac{6y^2-540000}{y^2}](https://tex.z-dn.net/?f=C%5E%7B%27%7D%28y%29%3D%5Cdfrac%7B6y%5E2-540000%7D%7By%5E2%7D)
![\dfrac{6y^2-540000}{y^2}=0\\6y^2-540000=0\\6y^2=540000\\y^2=\frac{540000}{6} =90000\\y=\sqrt{90000}=300](https://tex.z-dn.net/?f=%5Cdfrac%7B6y%5E2-540000%7D%7By%5E2%7D%3D0%5C%5C6y%5E2-540000%3D0%5C%5C6y%5E2%3D540000%5C%5Cy%5E2%3D%5Cfrac%7B540000%7D%7B6%7D%20%3D90000%5C%5Cy%3D%5Csqrt%7B90000%7D%3D300)
Recall,
![x=\frac{45000}{y}=\frac{45000}{300}=150](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B45000%7D%7By%7D%3D%5Cfrac%7B45000%7D%7B300%7D%3D150)
Since x=150, y=300
The dimensions that will be least expensive to build is 150 feet by 300 feet.
Answer
Step-by-step explanation:
To find the area of a shape multiply its height by its width. For a square you only need to find the length of one of the sides (as each side is the same length) and then multiply this by itself to find the area.
please mark me as brainliest.
This is actually really simple algebra. All you need to know is that Y= Mx + B
and M BEING YOUR SLOPE good luck
I believe the answer is C. It doesn't make sense to drop an object from -16 feet, and it doesn't make sense to have a -120 in the equation. It should be positive for it to come out right.