Hello from MrBillDoesMath!
Answer:
a(n) = -3n , n>= 1
Discussion:
a(1) = -3
a(2) = -6
a(3) = -9
a(4) = -12
The pattern looks like a(n) = -3n
Thank you,
MrB
Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

E-Z View: 40 + 4.95x
View the best: 25 + 5.95x
Equal monthly bills:
40 + 4.95x = 25 + 5.95x
5.95x - 4.95x = 40 - 25
x = 15
Answer: 15
4 is a coefficient and X and Y are variables so the -110 is the constant so there for the answer is D