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ser-zykov [4K]
3 years ago
13

When making a pie chart for this data what percentage of the cars would be sector labeled white include?

Mathematics
1 answer:
zysi [14]3 years ago
8 0

we are given

total number of white car is 88

now, we can find total number of cars

total number of cars =85+104+35+88+48

so, total number of cars =360

percentage of white car = ((total number of white car)/(total number of cars))*100

now, we can plug values

and we get

so, percentage of white car is

=\frac{88}{360}*100

=24.44

so, percentage of white car is  24.44%

so, option-A.........Answer



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What is the sum of the first 14 terms of the sequence an = 6n -12
mina [271]
When n = 1  first term  = -6 
n = 2  second term =  0
n = 3 third term = 6

n = 4 4th term = 12

so we have an Arithmetic sequence  first term = -6 and common difference = 6

Sum 14 terms  =  (14/2)[2*-6 + (14-1)*6]

 =  462  answer
6 0
4 years ago
Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p
GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2

you replace t1 from the first equation in the second equation:

(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}

Then, for t2 = 0 and t2=1/2 you obtain for t1:

t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths  intersect are:

r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)

B) You have the following two trajectories of two independent particles:

r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t

From the first equation you have:

t=1+2t\\\\t=-1

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0
3 years ago
Help!<br> this is urgent <br> i need it rn<br> ty in advance
olganol [36]

Answer:

The graph shows a steady declining plot as the aveage traffic volume increases. Since y axis is speed the correct answer is that as traffic volume increases the average vehicle speed decreases.

Step-by-step explanation:

4 0
2 years ago
What is the length of AB
sweet [91]

Answer:

6 units is the answer im pretty sure

6 0
3 years ago
PLEASEEEEE HELPPPPP<br><br><br> Quick 15 points
zheka24 [161]

Answer:

Neither

Step-by-step explanation:

Since we only know the measure of the angles, we can only say the triangles are similar, not congruent.  We need at least one side measurement on each triangle to determine if the triangles are congruent.  And it would have to be the same side measurement.  Then we could use ASA (Angle side Angle) or AAS ( Angle Angle side) to determine congruence.

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62+39 +79 = 180

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<A = 62 = <X = 62

<B = 39 = <Y = 39

<C = 79 = <Z = 79

This is shown by AAA similarity

5 0
3 years ago
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