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morpeh [17]
3 years ago
12

Graph the circle 2+ y2 - 14x + 2y + 41 = 0.

Mathematics
2 answers:
Luden [163]3 years ago
8 0

Answer:

we can not graph on here

Step-by-step explanation:

Murljashka [212]3 years ago
6 0

Answer:cant graph

Step-by-step explanation:

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is this a question?

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C

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The graph in this case represents exponential decline.

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Find the area of a circle with a circumfrence of 53.41 inches
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Can i get some help on my test please?
Veseljchak [2.6K]

Answer:

Not proportional.

Step-by-step explanation:

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Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
3 years ago
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