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VMariaS [17]
3 years ago
12

18 + what will get me 45

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

27

Step-by-step explanation:

Cloud [144]3 years ago
7 0
27 ( don’t ask what this is I need 20 characters long)
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contradictions!!!! i dont get them help me with 5 of them pleaseee i will mark you brainlest answer and everything
vodomira [7]
Contradictions usually mean they go against established rules. Squaring a negative number is one example if it is in math. But just think of anything that goes against what is known.  
3 0
3 years ago
which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

6 0
3 years ago
Given ƒ(x) = 7x − 22, find x when ƒ(x) = 48.
IRINA_888 [86]
X= 10. Should be pretty easy
6 0
3 years ago
The graph of g(x) is the result of translating the graph of f(x) = 3* six units to the right. What is the equation
Doss [256]

Answer:

Step-by-step explanation:

Pls help me with my question roo

3 0
3 years ago
Let u=<-5,1>, v=<7,-4> find 9u-6v
katrin2010 [14]
9u -6v = 9<-5, 1> -6<7, -4>
.. = <9*-5 -6*7, 9*1 -6*-4>
.. = <-87, 33>
8 0
3 years ago
Read 2 more answers
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