Answer:
7.5
Step-by-step explanation:

Answer:
x => y
0 => 0
2 => 3
4 => 6
-2 => -3
Step-by-step explanation:
The equation of a proportional relationship is represented as y = kx,
where, k = y/x
We are given that k = ³/2
This means that, equation of the relationship therefore would be:
y = ³/2x
Use this equation to solve for each missing value on the table given:
✔️Where, y = 0, substitute y = 0 into y = ³/2x to find x:
0 = ³/2x
0 * 2 = 3x
0 = 3x
0/3 = x
x = 0
✔️Where, x = 2, substitute x = 2 into y = ³/2x to find y:
y = ³/2(2)
y = 3
✔️Where, y = 6, substitute y = 6 into y = ³/2x to find x:
6 = ³/2x
6 * 2 = 3x
12 = 3x
12/3 = x
x = 4
✔️Where, x = -2, substitute x = -2 into y = ³/2x to find y:
y = ³/2(-2)
y = -3
Answer:
-0.8 < -3/4 < 7/10 < 3/4
Step-by-step explanation:
theyre decreasing
<u>ANSWER: </u>
x-intercepts of 
<u>SOLUTION:</u>
Given,
-- eqn 1
x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.
Now, let us find the zeroes using quadratic formula for f(x) = 0.

Here, for (1) a = 1, b= 12 and c = 24


Hence the x-intercepts of 
Answer:
84 is a solution.
Step-by-step explanation:
To find out if 84 is a solution or not, we plug in the value and simplify.
Therefore, 84 is a solution.