2 years ago

What is the product of (7X squared Y cubed)(3X to the fifth power Y to the eighth power)

Mathematics

1 answer:

g100num [7]2 years ago

6 0

Answer:

$21x^7y^{11}$

Step-by-step explanation:

$(7x^2y^3)(3x^5y^8)$

$7y^3\times \:3x^{2+5}y^8$

$7y^3\times \:3x^7y^8$

$7\times \:3x^7y^{3+8}$

$7\times \:3x^7y^{11}$

$21\times x^7y^{11}$

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Step-by-step explanation:

We are given four sets of relations as

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