Question

What is the product of (7X squared Y cubed)(3X to the fifth power Y to the eighth power)

Answer 1

Answer:

$21x^7y^{11}$

Step-by-step explanation:

$(7x^2y^3)(3x^5y^8)$

$7y^3\times \:3x^{2+5}y^8$

$7y^3\times \:3x^7y^8$

$7\times \:3x^7y^{3+8}$

$7\times \:3x^7y^{11}$

$21\times x^7y^{11}$