Answer:
Interest: $50 | Total: $250
Step-by-step explanation:
You are going to want to use the simple interest formula for this. The one below is modified for solving the interest earned.

<em>I = interest amount
</em>
<em>P = principal amount
</em>
<em>r = interest rate (decimal form)
</em>
<em>t = time</em>
<em />
Now we can plug in the values into the equation:


This means that Ariane is charged $50 worth of interest. She has to pay back $250 total dollars.
Answer:
Look for the same entry in both (all) tables.
Step-by-step explanation:
We assume here that the system of equations consists of two equations in two variables. If there are more equations in more variables, the general approach is the same.
A "solution" to a system of equations is a set of variable values that satisfies all equations of the system simultaneously. A table for one equation will generally list sets of variable values that satisfy that equation. <em>When the same set of values appears in the table for each of the equations, then that set of values is the solution</em>.
__
<u>Example</u>
The attachment shows tables for two equations:
Highlighted are the table entries that are the same for both equations. This is the solution to the system of equations. (x, y) = (3, 6) satisfies both equations:
I don't understand the pattern
Answer:
A. 71/2 = 35.5 + 32/3= 10.7 + 41/4= 10.3
35.5 + 10.7 + 10.3 = 56.5
B. 21÷2 = 10.5
56.5 ÷ 10.5 = 5.380952381
5 pictures frames
Answer:
The general term of the sequence is given by
T
n
=
a
n
2
+
b
n
+
c
The general term of the sequence is given by
T
n
=
a
n
2
+
b
n
+
c
Calculate a,b and c
Determine the 12th term of the sequence.
grade12 general-term sequence series
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1 Answer
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T3 - 6=6
T3=12
then T2-T1=4
6-T1=4
T1=2
T4-T3=8
T4-12=8
T4=20
Therefore terms= 2,6,12,20
1st difference= 4,6,8
2nd difference= 2,2,....
2a=2
a=1
3a+b=4
3(1) + b=4
b= 1
a+b+c= 2
c= 2-1- 1= 0
giving Tn= n^2 + n
T12 = 12^2 + 12 = 156