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3 years ago

Fit a quadratic function to these three points: (-1,-11) , (0,-3) and (3,-27)

Mathematics

1 answer:

notka56 [123]3 years ago

6 0

It is -10 then -3 then -24

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it is presentation day in class and your instructor is drawing names from a hat to determine the order of the presentations. If

Simora [160]

ANSWER:

The probability is 1/43680

STEP-BY-STEP EXPLANATION:

We have the following:

0. The probability that Morgan is chosen first = 1/16. Now there are 15 students left after this.

1. The probability that Harmony is chosen second = 1/15. Now there are 14 students left after this.

2. The probability that Kenny is chosen third = 1/14. Now there are 13 students left after this.

3. The probability that Ben is chosen fourth = 1/13.

Therefore, the required probability is:

$\begin{gathered} p=\frac{1}{16}\cdot\frac{1}{15}\cdot\frac{1}{14}\cdot\frac{1}{13} \\ p=\frac{1}{43680} \end{gathered}$

7 0

1 year ago

Which of the following fractions is in simplest form?<br> 9/16<br> 8/14<br> 6/20<br> 15/35

disa [49]

9/16
thats the correct answer bro

3 0

4 years ago

Read 2 more answers

Three 24 hour clocks show the time to be 12 noon. One of the clocks is always correct, one loses a minute every 24 hours, and on

umka21 [38]

All three clocks will show the same time in 1 day.

5 0

3 years ago

Choose the property that justifies the following statement. If x = 2 and x + y = 3, then 2 + y = 3.

user100 [1]

.................................

4 0

3 years ago

Please help with this and explain how to do it, I'll give 15 points

MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = $\frac{10}{2}$ = 5 cm

Volume of the outer ball $V_{1}$ = $\frac{4}{3}\pi (r)^3$

= $\frac{4}{3}\pi (5)^3$

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball $V_{2}$ = $\frac{4}{3}\pi (4)^3$

Volume of the metal used in the metallic ball = $V_{1}-V_{2}$

= $\frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}$

= $\frac{4}{3}\pi [(5)^3-(4)^3]$

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0

3 years ago