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Ira Lisetskai [31]
3 years ago
12

Choose the property that justifies the following statement. If x = 2 and x + y = 3, then 2 + y = 3.

Mathematics
1 answer:
user100 [1]3 years ago
4 0

  .................................

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Help me please with the steps on how you can find the number of solutions or zeros with these questions!
arsen [322]

Answer:

2x²+5x-9=0

using quadratic formula

a=2 b=5 c=-9

x=[-5±√5²-4(2)(-9)]/2(2)

x=[-5±√97]/4

the zeros are( -5±√97)/4

6 0
3 years ago
Find d<br><br> a * a * a = 216<br> a * b * c = 96<br> b * c = 52<br> a + b + c = d
Slav-nsk [51]

a\cdot a\cdot a=216\\\\a^3=216\to a=\sqrt[3]{216}\\\\\boxed{a=6}\\\\\text{Substitute}\ b\cdot c=52\ \text{to the second expression}\ a\cdot b\cdot c=96:\\\\abc96\ \wedge\ bc=52\to a(52)=96\qquad\text{divide both sides by 52}\\\\a=\dfrac{96}{52}\to a=\dfrac{24}{13}\neq6

a = 6 and a = 24/13  FALSE!!!

<h3>Answer: NO SOLUTION.</h3>
3 0
3 years ago
What are 2 possible dimensions for a rectangular prism with a surface area of 600 square inches
Anestetic [448]
Divide 600 by 3 and get 200 so the possible dimensions would be 200 by 200by 200
6 0
2 years ago
A 46 gram sample of a substance that is used to sterilize surgical instruments has a k-value of 0.1374. Find the substance's hal
mars1129 [50]

Answer:

  t=5.0days

Step-by-step explanation:

Using the formula for the exponential decay that is N=N_{0}e^{-kt}, we have N=\frac{1}{2}{\times}46=23, N_{0}=46 and k=0.1374.

Thus, N=N_{0}e^{-kt} becomes

23=46{\times}e^{-0.1374t}

\frac{23}{46}=e^{-0.1374t}

\frac{1}{2}=e^{-0.1374t}

Taking log on both sides, we get

ln(\frac{1}{2})={-0.1374t}

t=\frac{ln\frac{1}{2}}{-0.1}

t=\frac{-0.6931}{-0.1374}

t=5.0days

4 0
3 years ago
in a reverse stock split , the number of outstanding shares is reduced while the market price shares stays the same ? true or fa
Art [367]

False!


The first statement is correct, a company's traded shares reduces *BUT* that results in an increase in the par value or earnings per share. Same goes for a stock.


- Dysmy ☕

3 0
3 years ago
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