Question

Please help with this and explain how to do it, I'll give 15 points

Answer 1

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = $\frac{10}{2}$ = 5 cm

Volume of the outer ball $V_{1}$ = $\frac{4}{3}\pi (r)^3$

                                         = $\frac{4}{3}\pi (5)^3$

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball $V_{2}$ = $\frac{4}{3}\pi (4)^3$

Volume of the metal used in the metallic ball = $V_{1}-V_{2}$

                                                                           = $\frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}$

                                                                           = $\frac{4}{3}\pi [(5)^3-(4)^3]$

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.