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Arte-miy333 [17]
3 years ago
5

126 = -61-7 - 2n) ?​

Mathematics
2 answers:
Lilit [14]3 years ago
8 0

Answer:

X=-97

Step-by-step explanation:

Lunna [17]3 years ago
4 0

Answer: n=-97 Promise me The answer is correct

Step-by-step explanation:

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Alicia used 4 gallons of gasoline to travel 90 miles. At the same rate, how far can she travel on a full tank that holds 18 gall
MrRa [10]
90 miles/4 gallons = 22.5 miles/1 gallon.

22.5 miles*18 gallons= 405 miles

the answer is 405 miles
6 0
3 years ago
Halp me please i don't wanna fail...I wanna pass this test ;--; (MUST BE A EXPRESSION)
vaieri [72.5K]

Answer:

155+27n

Step-by-step explanation:

hope this helps

6 0
3 years ago
Read 2 more answers
Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___
devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 cm^2

and specific resistance (ρ) = 1.8 \times 10^{-6} ohm-cm.

Use the formula  R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, R=\frac{1.8 \times 10^{-6} \times 270}{0.030} ohm

Simplify:

R = 0.0162 ohm = 1.62\times 10^{-2} ohm

Therefore, the resistance of copper wire is,  1.62\times 10^{-2} Ω


8 0
3 years ago
In a​ film, a character is criticized for marrying a woman when he is three times her age. He wittily​ replies, "Ah, but in 25ye
Sonbull [250]

Answer:age of the man: 75 age of the woman:25

Step-by-step explanation:

First, We need to define the variables

x: age of the man

y: age of the woman

at the first time he has three times her age

x=3y                (1)

in 25 years time

(x+25)=2(y+25)                 (2)

we clear the equation

X+25=2y+50

X=2y+25

we substitute in the (1) equation:

2y+25=3y

y=25

x=3*25=75

5 0
3 years ago
Read 2 more answers
The base of a rectangle is 15cm the perimeter is at most 94 cm. Write and solve an inequality to find the possible heights of th
tino4ka555 [31]
15 x 6 = 90 + 4 = 94 that's what I would do 
4 0
3 years ago
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