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marishachu [46]

3 years ago

8

Sarah has going to work for 60 days. On 39 of those days she arrived at work before 8:30 AM. On the rest of the day she arrived

after 8:30 AM. What is experimental probability she will arrive after 8:30 AM on the next day she goes to work.

1 answer:

Sonbull [250]3 years ago

5 0

I think she will arrive at work BEFORE 8:30

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Is this positive, negative, none or you cannot tell. Will mark CORRECT brainliest

pshichka [43]

Answer:

Positive correlation if right. Atleast consider brainlist:)

Step-by-step explanation:

3 0

3 years ago

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Can anyone solve this question??? plss plsss its my request to all if any one can solve this question I will mark him/ her the b

almond37 [142]

Answer:

a) ∠EAB = 180° - 90° - 30° = 60°

∠EBA = 180° - 90° - 60° = 30°

a) ∠EBA = 30°

b) ∠DCA = 180° - 90° - 30° = 60°

∠EBA ≅ ∠DAC, ∠EAB ≅ ∠DCA, ∠AEB ≅ ∠CDA

ΔEBA ≅ ΔDAC because of the AAA postulate

c) EB ≅ DA, EA ≅ DC, AB ≅ CA

d) AB = CA given

sin ∠EAB = EB/AB (sin 60°) EB = (0.8660)AB

cos ∠EAB = EA/AB (cos 60°) EA = (0.5)AB

cos ∠DAC = AD/CA (cos 30°) AD = (0.8660)CA

sin ∠DAC = CD/CA (sin 30°) CD = (0.5)CA

ED = EA + AD

ED = (0.5)AB + (0.8660)CA

since AB = CA, ED = 1.366CA

since EB = (0.8660)AB and AB = CA, then EB = 0.866CA

since CD = 0.5CA,

EB + CD = 0.866CA + 0.5CA = 1.366CA

EB + CD = 1.366CA

1.366CA = 1.366CA

Proof: ED = EB + CD

7 0

3 years ago

I dont get 5 and 6 help me!!!!

Kitty [74]

Answer:

5) A

6) A

Step-by-step explanation:

5) With the sides of the rectangle being dilated, multiply the side lengths by the scale factor

7.5(2.2) and 3(2.2)

16.5 and 6.6

6) Multiply the coordinates by the scale factor as dilations work as (x, y) -> (kx, ky)

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3 years ago

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cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta

NikAS [45]

First calculate $\sin\theta$ .

$\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}$

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

$\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\
\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}$

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3 years ago

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Which expression is equivalent to -3(2m-1)-n

ZanzabumX [31]

<span>-3(2m-1)-n

First we multiply -3 to the first term of the expression

---------- > ( -3*2m + (-3)*(-1) ) - n

</span>---------- > ( -6m + 3 ) - n<span>

-----------> -6m -n + 3

Then, we divide and multiply by -6, (the expression remains the same)

</span>
---- > (-6/-6)* (-6m -n + 3)<span>

---- > -6*[m + (n/6) - 1/2]
</span>
The answer is -6*[m + (n/6) - 1/2]

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3 years ago

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