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Bas_tet [7]
3 years ago
9

How high is the building (ie. from what height was the potato launched) if h=-2(t-3)2+32

Mathematics
1 answer:
Llana [10]3 years ago
5 0

Answer:

14

Step-by-step explanation:

To find the height from which the potato was launched, you need to set the time to 0 (since that is at the beginning). Plugging this into the equation, you get:

h=-2(0-3)^2+32

h=-2(9)+32

h=32-18

h=14

Hope this helps!

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vichka [17]

Answer:

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Step-by-step explanation:

The value of i is i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4} in term of i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}

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Substituting the value,

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Now \sqrt{-81} can be written as follows,

\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}

Applying radical multiplication rule,

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2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i

Simplifying,

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Collecting similar terms,

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Combining similar terms,

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The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

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