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Dmitry_Shevchenko [17]
4 years ago
9

Can somebody please help me with this?

Mathematics
1 answer:
Natali5045456 [20]4 years ago
6 0
I would say C, but it also might be d
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S\frac{O}{H} C\frac{A}{H} T\frac{O}{A} or Sin\frac{Opposite}{Hypotenuse}Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Opposite}{Adjacent}


At the point/angle E:

- the adjacent side(side <u>next to</u> the point/angle) is ED

- the opposite side(side of the triangle <u>across</u> from the point/angle) is DF

- the hypotenuse (the<u> longest side</u> of the triangle) is EF.


sin ∠E = \frac{opposite}{hypotenuse}

sin ∠E = \frac{6}{10} = \frac{3}{5} (simplified)

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