Answer:
1. x = 7
2. x = -5
Step-by-step explanation:
1. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: 2*x+5*(6*x-9)-(179)=0
Pull out like factors 6x - 9 = 3 • (2x - 3)
(2x + 15 • (2x - 3)) - 179 = 0
Pull out like factors: 32x - 224 = 32 • (x - 7)
Solve: x-7 = 0
Add 7 to both sides of the equation = 7
2. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: -40-(6*x-5*(-4*x-18))=0
Pull out like factors: -4x - 18 = -2 • (2x + 9)
-40 - (6x - -10 • (2x + 9)) = 0
Pull out like factors: -26x - 130 = -26 • (x + 5)
-26 • (x + 5) = 0
Solve: x+5 = 0
Subtract 5 from both sides of the equation: x = -5
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Answer:
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Step-by-step explanation:
Answer:
5^(3)i^(9)= five cubes times i to the power of 9=125i
Step-by-step explanation:
Raise 5 to the power of 3
rewrite i9 as (i^4)2^i
so, you get 125((i^4)^2i)
i^4=1
125(1^2i)
125i
Total cost for tiles and paints is $924.
Step-by-step explanation:
We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.
The paint will be required for 4 walls and ceiling.
Let us find area of walls and ceiling.
Therefore, the area of walls and ceiling is 1410 square meters.
Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,
Therefore, the total painting cost is $564.
Tiles will be required for floor. Let us find the area of floor.
Given: 1m squared floor tiles costs $3. So,
Therefore, the total cost for tiles is $360.
Now let us find combined total cost of tiles and paint.
Therefore, the combined total cost of tiles and paint is $924.
