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Reika [66]
4 years ago
7

What is the mean for 63,54,49,62,48,53,50?

Mathematics
2 answers:
Ira Lisetskai [31]4 years ago
4 0

Answer:

54.14

Step-by-step explanation:

Add them all up then divide by 7 because that is the number of numbers in the data set and you get a long decimal but I just rounded to the hundredths place

ddd [48]4 years ago
4 0

Answer:

54.1428

Step-by-step explanation:

To find the mean is to find the average of a group of numbers. To find it you add up all of the numbers in the set, and then divide by the number of numbers in the set. 63 + 54 + 49 + 62 + 48 + 53 + 50 = 379. Because the set has seven numbers in the set, you divide 379 by 7. This will give you the mean or average, which is 54.1428

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3 years ago
A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank
harkovskaia [24]

Answer:

The value  is P_o = \$ 561958.9

Step-by-step explanation:

From the question we are told that

  The capacity of the metal  tank is  C =  2000 \  gallon

   The duration usage is  t = 15\ years \ ago

   The cost of 2000-gallon tank 15 years ago is P =  \$100,000

    The capacity of the second tank considered is C_1 = 5,000  

    The power sizing exponent is e = 0.57

     The initial construction cost index is  u_1 = 180

      The new construction after 15 years cost index is  u_2 =600

Equation for the power sizing exponent is mathematically represented as

      \frac{P_n}{P} = [\frac{C_1}{C} ]^{e}

=> Here P_n is the cost of 5,000-gallon tank as at 15 years ago  

So

     P_n  =  [\frac{5000}{2000} ] ^{0.57} * 100000

      P_n  =  \$168587.7

Equation for the cost index exponent is mathematically represented as

      \frac{P_o}{P_n}  =  \frac{u_2}{u_1}

HereP_o is the cost of 5,000-gallon tank today

So

       \frac{P_o}{168587.7}  =  \frac{600}{180}

=>    P_o = \frac{600}{180} * 168587.7

=>      P_o = \$ 561958.9

8 0
4 years ago
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