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3 years ago

6

What would be the first step you would take in simplifying 6 - 3+ 5 x 2 ?

2 answers:

OleMash [197]3 years ago

8 0

Answer:

Multiply ; (5 ×2)

Step-by-step explanation:

Further explanation

$6-3+5\cdot \:2\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:5\cdot \:2\::\quad 10\\=6-3+10\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:6-3+10\:\\:\quad 13$

Darya [45]3 years ago

4 0

The first step you would take would be multiplying 5x2

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Read 2 more answers

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

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(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

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⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

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⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

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(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

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3 years ago

On interchanging two digits of the number 2643, it decreased by 180. Which two digits of 2643 might have been interchanged?

iris [78.8K]

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Explanation:

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3 years ago

matrenka [14]

Answer:

Step-by-step explanation:

D.works many year for a nation

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3 years ago