where
. The second term of the expansion occurs when
.
So the second term of the expansion of
is
a = 56
given 28 = 
a
multiply both sides by 2 to eliminate the fraction
56 = a
As a check
× 56 = 28 ← True
Ah usatestprep ok 90% of awnsers are C so pick C
Answer:
0
Step-by-step explanation:
The smallest perfect cube would be 0 since it cannot be negative and zero raised to the third power would still be 0
Answer:
76
Step-by-step explanation:
A + B = 127
5.80A + 4.25B = 657.55
Solve with substitution.
5.80A + 4.25(127 − A) = 657.55
5.80A + 539.75 − 4.25A = 657.55
1.55A = 117.80
A = 76
