Question

What’s the answer??? (SOMEONE PLEASE HELP)

Answer 1

- $\frac{3y}{x^{2} }$

separate the factors as products

$\frac{-24}{8}$ × $\frac{x^{4} }{x^{6} }$ × $\frac{y^{3} }{y^{2} }$

using the rule of exponents

$\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ if m > n

and $\frac{1}{a^{(n-m)} }$ if n > m

= - 3 × $\frac{1}{x^{(6-4)} }$ × $y^{(3-2)}$

= - 3 ×  $\frac{1}{x^{2} }$ × y = - $\frac{3y}{x^{2} }$

Answer 2

$\frac{ - 24 {x}^{4}{y}^{3} }{8 {x}^{6} {y}^{2} } = \frac{ - 3y}{ {x}^{2} }$