Quadratic equation is

WHEN

So, to make this true subtract 7 from each side.
The equation is now
7

- x - 7 = 0
Values for a, b, and c: a = 7, b = -1, c = -7
Plug these variables into the quadratic equation.
Square -1 to get 1 and multiply -4 x 7 x -7 to get 196.

Multiply 2 x -7 to get -14, the denominator, and add 1 to 196.
Since 197 is not a square number, and I don't know if you want to leave it in radical form or not, I will just because it's easier to understand.
Hope this helps!
This is a slope intercept form problem! The equation would be modeled as in the image. It would be modeled as so because 2 is the y-intercept, meaning that is where we begin on the graph (the point location is (0,2). From there, we would move up 1 point and to the right 3 points because slope is represented by rise over run. Since 1/3 has a variable beside it, we know 1/3 is the slope. With that being said, the equation would be graphed by starting at (0,2) on the graph and moving up 1 and to the right 3 points each time. If you need any help, let me know and I will gladly assist you.
11/3 x 9/4
Is 33/4 which is 8 1/4
Give me a thx if this helps