Answer:
The complete Matlab code along with step by step explanation is provided below.
Matlab Code:
function Req=ParallelR(Number)
Number=input('Please enter the number of resistors: ');
if Number>10 | Number<=0
disp('Invalid input')
return
end
R=0;
for i=1:Number
r=input('Please enter the value of resistor: ');
R=R+1/r;
end
Req=1/R;
end
Explanation:
Parallel resistance is given by

First we get the input from the user for how many parallel resistors he want to calculate the resistance.
Then we check whether the user has entered correct number of resistors or not that is from 1 to 10 inclusive.
Then we run a for loop to get the resistance values of individual resistors.
Then we calculated the parallel resistance and keep on adding the resistance for N number of resistors.
Output:
Test 1:
Please enter the number of resistors: 3
Please enter the value of resistor: 10
Please enter the value of resistor: 20
Please enter the value of resistor: 30
ans = 60/11
Test 2:
Please enter the number of resistors: 11
Invalid input
Test 3:
Please enter the number of resistors: 0
Invalid input
Answer:
Page Setup Grouping.
Explanation:
In Microsoft Word, Columns break up the page into, at max, 13 columns, and at minumum, 2. The way you go about doing this is
- Go to the Layout Tab
- Go to the Page setup Grouping
- Click on the Columns Action
- In the Dialog Box, choose either from one of the presents, or custom make your own column settings.
- Click Okay
- Done!
Wich statements ? I don’t see anything
Answer:
Multiple devices can be connected
Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}