Answer:
mystr = input("Enter a string ")
length = len(mystr)
while length<10:
mystr = input("Enter a string ")
length = len(mystr)
if(length>=10):
break
if len(mystr)%2==0:
print(mystr.lower())
else:
print(mystr.upper())
Explanation:
The variable mystr is used to save user's input which is received with the input function
A second variable length is used to save the length of the input string Using a while statement the user is continually prompted to enter a string while length is less than 10.
If length is greater or equal to 10. We check for even or odd using the modulo (%) operator.
We use lower() and upper() to change the case of the string
Answer:
Computerised accounting systems have numerous benefits to them and below are the top nine points as to why you should be using them with your business.
Automation. ...
Data Access. ...
Accuracy. ...
Reliability. ...
Speed. ...
Security. ...
Scalable. ...
Visuals.
Explanation:
hope this helps!
Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn