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AleksandrR [38]
3 years ago
13

Which statement is true about the given set of data? {(4, 0), (5, 0), (8, 0), (11, 0)}

Mathematics
1 answer:
Anni [7]3 years ago
7 0

Answer:

a

4,5,8,11 are the domain

Step-by-step explanation:

x is always the domain, input and It could also be a function but I don't think that only four five eight and 11 are functions so I would go with a

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2/3x=10 thankyou for helping me
Novay_Z [31]
(2/3)x = 10
(3/2)(2/3)x = 10(3/2)
x = 30/2 = 15
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What is the range of the function below:<br> Let a(x)=x+2 such that x is a positive integer.
liubo4ka [24]
So all positive integers is the domain (the number  you can use)

and the range (the numbers you get when you put the numbers in the domain in) is all positive integers more than 2
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Given the sample −4, −10, −16, 8, −12, add one more sample value that will make the mean equal to 3.
Agata [3.3K]

Answer: The value to add to the set is 52

=======================================================

For a moment, ignore the extra value we'll add in later.

The given set of values add to -34.

Let x be the extra value we add in. It adds to the -34 to get -34+x, then we divide by 6 because the set {-4,-10,-16,8,-12,x} has 6 items.

So we get the mean (-34+x)/6

Set this equal to the mean we want (3) and solve for x

(-34+x)/6 = 3

-34+x = 6*3

-34+x = 18

x = 18+34

x = 52

The set {-4,-10,-16,8,-12,x} updates to {-4,-10,-16,8,-12,52} and this set has a mean of 3.

6 0
2 years ago
What is the value of the digit 6 in 102,653
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That would be the hundred thosand place
6 0
3 years ago
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7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
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