We want to find a solution to the initial value problem:
We can start by integrating the equation once:
Using the initial condition 
, we can determine the integration constant 
:
Therefore, we have:
We can now integrate again:
The integration constant 
is determined by using 
:
Finally, the solution is:
We need to put ur equation in y = mx + b form ...and the m will be ur slope and the b will be ur y int
so basically, we solve for y...
2x + y = 3....subtract 2x from both sides
y = -2x + 3
y = mx + b
y = -2x + 3......slope(m) = -2 and y int (b) = 3 <==
Answer: x^2+y^2+2x-18y+18=0 in standard form is (x+1)^2+(y-9)^2=64
Answer:
(-12,11)
Step-by-step explanation:
x + 2y = 10
3x + 4y = 8
(-2)x + (-2)2y = (-2)10
3x + 4y = 8
-2x - 4y = -20
3x + 4y = 8
Add to eliminate:
x = -12
Substitute x to solve y:
x + 2y = 10
(-12) + 2y = 10
-12 + 2y = 10
2y = 10 + 12
2y = 22
y = 22 ÷ 2
y = 11
Check:
x + 2y = 10
(-12) + 2(11) = 10
-12 + 22 = 10
10 = 10
Answer:
Step-by-step explanation:
C:27
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