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g100num [7]
3 years ago
13

there were a total of 68 basketball games during the lockout-shortened 2012 NBA season. this season was played over the course o

f five months including playoffs in the NBA Finals .how many basketball games were played each month, ifeach week has the same number games?
Mathematics
1 answer:
alisha [4.7K]3 years ago
3 0
The answer is :13...3
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Dafna1 [17]

Answer:

Angle 4 as it is across from 1 and is equal in size

Step-by-step explanation:

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. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an
Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when X = 59.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{59.5 - 56}{1.12}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0
2 years ago
If your starting salary were $40,000 and you received a 3% increase at the end of every year for 15 years, what would be the tot
Dmitry [639]

T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15


Multiply the above equation by 1.03 giving


1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16


Now subtract the first equation from the second to give


0.03T = 40000(1.03)^16 - 40000


0.03T = 40000(1.03^16 - 1)


0.03T = 24188.26


T = 24188.26 / 0.03 = $806275.25


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Answer: 5.5

Step-by-step explanation:

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Answer:

= and \leq and \geq

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Greater than or equal to works because of the equal sign.

Less than or equal to also works because of the equal sign.

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