A bucket of water with mass 5 kg sits on the ground with a coefficient of static friction of 0.35. What is the maximum force of
1 answer:
Answer:
The force of static friction is 17.15 N
Explanation:
It is given that,
Mass of the bucket, m = 5 kg
The coefficient of static friction is,
We need to find the maximum force of static friction. It is given by :
F = 17.15 N
So, the force of static friction is 17.15 N. Hence, this is the required solution.
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is the wavelength
f is the frequency of the wave
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(because the wavelength is the distance between two successive crests). The period of the wave is 6 s, and the frequency is the reciprocal of the period:
Therefore, the speed of the waves is
2) The speed of sound in air is
. The frequency of the note is f=400 Hz, so we can find its wavelength by using the same relationship we used at point 1)
Since you are sitting at a distance of d=184 m from the source of the sound wave, the number of wavelengths between you and Barry is
So, there are approximately 214 fully wavelengths between you and Barry.
2b) The time delay between the time the note is played and the time you hear it corresponds to the time the sound takes to arrive to your ear, therefore the distance divided by the speed of sound:
3) The wavelength of the ultrasound wave is
while its speed is the speed of sound: , therefore its frequency is
4) The period of the wave is T=2 s, so the frequency is
and the spacing between the crests, which corresponds to the wavelength, is
Therefore, the speed of the wave is
where
f is the frequency of the wave
For the wave in this problem, the distance between two successive crests is 15 m, this means its wavelength is
Therefore, the speed of the waves is
2) The speed of sound in air is
Since you are sitting at a distance of d=184 m from the source of the sound wave, the number of wavelengths between you and Barry is
So, there are approximately 214 fully wavelengths between you and Barry.
2b) The time delay between the time the note is played and the time you hear it corresponds to the time the sound takes to arrive to your ear, therefore the distance divided by the speed of sound:
3) The wavelength of the ultrasound wave is
4) The period of the wave is T=2 s, so the frequency is
and the spacing between the crests, which corresponds to the wavelength, is
Therefore, the speed of the wave is