Question

Two vehicles approach an intersection: a truck moving eastbound at 16.0 m/s and an SUV moving southbound at 20.0 m/s. Suppose that the x-axis is directed eastward and the y-axis is directed northward. Find the magnitude of the velocity vector of the truck relative to the SUV.

Answer 1

Answer:

The value of magnitude of the velocity vector of the truck relative to the SUV   $V_{xy}= 25.62 \frac{m}{sec}$

Explanation:

Velocity of the truck $V_{x}$ = 16 $\frac{m}{s}$

Velocity of the SUV $V_{y}$ = - 20 $\frac{m}{s}$

The magnitude of the velocity vector of the truck relative to the SUV is

$V_{xy} =\sqrt{ V_{x} ^{2} + V_{y}^{2}}$

Put the value of $V_{x}$ & $V_{y}$ in the above equation we get

$V_{xy} = \sqrt{(16)^{2} + (-20)^{2}}$

$V_{xy} = \sqrt{656}$

$V_{xy}= 25.62 \frac{m}{sec}$

This is the value of magnitude of the velocity vector of the truck relative to the SUV.