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MArishka [77]
3 years ago
9

Another model rocket is accelerating at a rate of 3 m/s2 with a force of 1 N. What is the mass of the rocket?​

Physics
1 answer:
madreJ [45]3 years ago
5 0

Answer:

60M

Explanation:

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In an experiment to determine the fractal dimension of crumpled newspaper, mass and radius were plotted on log-log paper. Select
777dan777 [17]

Answer:

fractal dimension is 0.1092

Explanation:

given data

vertical distance V = 44 mm = 0.044 m

horizontal distance H = 30 mm = 0.030 m

to find out

fractal dimension

solution

we will apply here fractal dimension formula that is

logV = ( 1 - fractal dimension) logH  ...................a

put here all value in equation a

we get

fractal dimension = 1 - \frac{logV}{logH}

fractal dimension = 1 - \frac{log0.044}{log0.030}

fractal dimension = 1 - \frac{-1.35654732351
}{-1.52287874528
}

fractal dimension = 0.1092217

so fractal dimension is 0.1092

8 0
3 years ago
Which phrase best describes matter? A. Matter is made of atoms and is too small to see. B. Matter is solid and heavy. C. Matter
QveST [7]
And the answer is C. Matter it has mass and it takes up spaces.  

Hopes it helped you.

-Charlie
4 0
3 years ago
Read 2 more answers
A stone is thrown vertically upwards, reaches a highest point, and returns to the ground. When the stone is at the top of its pa
juin [17]
From the time the stone leaves the thrower's hand until it hits the ground, its acceleration is 9.8 m/s^2 downward. Or whatever the acceleration of gravity is on the planet where the toss takes place. It doesn't even have to be tossed vertically. It can be tossed horizontally, or down, or slanty. The answer is the same.
7 0
3 years ago
If an unbalanced force acts on an object, what will happen?
vaieri [72.5K]

Answer:

<h2>An unbalanced force acting on an object causes it to accelerate. There are two points to note about the acceleration of an object when an unbalanced force acts on it. The bigger the unbalanced force acting on the object the bigger the acceleration of the object.</h2>

Explanation:

3 0
3 years ago
A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. initially, the mass is released from rest fro
Anni [7]
When the spring is in the equilibrium we know that force of the spring is equal to the force of gravity. This allows us to find the spring constant k.
mg=ky_0\\ k=\frac{mg}{y_0}=2304\frac{N}{in}
When the system is not in equilibrium the force of gravity and force of the spring are not going to be the same. There is going to be a force acting on the weight.
F=ma=mg-kl\\ ma=mg-k(y_0+y)\\ ma=mg-ky-ky_0\\ ky_0=mg\\ ma=mg-ky-mg\\ ma=-ky\\ \frac{d^2y}{dt^2}+\frac{k}{m}y=0
This is the same differential equation we get for the horizontal spring system. The general solution to this equation is:
y(t)=A\sin(\omega t)
Where:
\omega=\sqrt{\frac{k}{m}};\\&#10;A=y(0)=4$in
So our final equation will be;
y(t)=4\sin(9.8 t)
7 0
3 years ago
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