Answer:
170 Mbps
Explanation:
Time taken to put data on to the link T1 = 50kB / 1 Gbps = 0.0004096
Time taken for transmission T2 = 2 milliseconds = 2 * 10-3
--> throughput = ( 1 / (1+T2/T1) ) * bandwidth of link
= ( 1 / (1 + 4.8828125) ) * 1 Gbps
= 0.16998672 * 1 Gbps
= 169.98672 Mbps
= 170 Mbps.
Solution:
A(n) extranet is a lan that uses the same technologies as the internet but is provided to invited users outside the organization who access it over the internet.
An extranet is a private network that uses Internet technology and the public telecommunication system to securely share part of a business's information or operations with suppliers, vendors, partners, customers, or other businesses. An extranet can be viewed as part of a company's intranet that is extended to users outside the company. It has also been described as a "state of mind" in which the Internet is perceived as a way to do business with other companies as well as to sell products to customers.
This is the right answer.
All it does it let you browse the internet, but whatever you look up, it isn't put on your browser history.
Answer:
Explanation:
i) On a cold day, Capacity = (66 X 910 X 10∧-9) F
Charge, Q = (66 X 910 X 10∧-9) X 5050 = 0.30 Columb
Current, I= 5050/131013 = 0.039 Amp (where Resistance = 131013 ohms)
Time, t= 0.30/0.039 = 7.7 seconds
ii) On a humid day, Capacity = (77 X 910 X 10∧-9) F
Charge, Q = ( 77 X 910 X 10∧-9) X 5050 = 0.35 Columb
Current, I= 5050/6106 = 0.83 Amp ( where Resistance = 6106 ohms)
Time, t= 0.35/0.83 = 0.42 h or 0.42 X 60 mins = 25 mins
