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Tju [1.3M]
3 years ago
10

Find the height of a soup can if the area of the label is 302 square centimeters and the radius of the can is 4 centimeters. Rou

nd to the nearest whole number. show work please ...?
Mathematics
1 answer:
amid [387]3 years ago
8 0
To answer this, we assume that the can is in cylindrical shape. The of its label would correspond to an area of a rectangle where the length would be the circumference of the base of the can. We calculate as follows:

C = 2πr = 2π(4) = 8π = L

A = LH = 8π(H) = 302
H = 12 cm

Hope this answers the question. Have a nice day.
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Write the equation of a line in slope-intercept form that goes through the points
Stella [2.4K]

Answer: The equation in slope-intercept form is y=2x-11

Step-by-step explanation: Slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To find the slope, you find the difference between the y values divided by the difference between the x values. -5-(-9) = 4, and 3-1 is 2. 4/2 is 2, so m = 2. Since the slope is 2, it states for every x you move on the right you move 2 up. But we are trying to get the y-intercept, so x = 0. We are subtracting 1 in our x value, so we move 2 downwards. We subtract 2 from -9 which gives us -11, which is our y-intercept.

Hope this helps!

5 0
2 years ago
The value of a boat is depreciating at a rate of 7% per year. In 2004 the boat was worth $180,000. Whats the value in 2009?​
ankoles [38]

Answer:

$117,000

Step-by-step explanation:

-0% 2004

-7% 2005

-14% 2006

-21% 2007

-28% 2008

-35% 2009

180,000 x 0.35 (35%) = 63,000

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7 0
3 years ago
I need help asap with this
tatyana61 [14]

Answer:

51°

Step-by-step explanation:

Given

<QPR = 39°

<PQR = 90° ( inscribed angle in semi circle)

Now

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39° + 90° + <PRQ = 180°

<PRQ = 180° - 39° - 90°

<PRQ = 51°

Hope it will help :)

5 0
3 years ago
3 equivalent of expressions using distributive 300x + 100y
Musya8 [376]
Well you could do 5(60x+20y), 100(3x+y), and 2(150x+50y)
6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=400%20%5Cdiv%205%200" id="TexFormula1" title="400 \div 5 0" alt="400 \div 5 0" align="absmiddl
lyudmila [28]
The answer is 8 , 400/50=8
8 0
3 years ago
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