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2 years ago

12x+7<−11 OR 5x−8>40 solve for x

Mathematics

2 answers:

Flura [38]2 years ago

7 0

Answer:

x < -3/2 OR x > 9 3/5

Step-by-step explanation:

12x+7<−11 OR 5x−8>40

Solve the inequalities separately

12x+7<−11

Subtract 7 from each side

12x+7-7<−11 -7

12x < -18

Divide each side by 12

12x/12 < -18/12

x < -3/2

Then solve the other inequality

5x−8>40

Add 8 to each side

5x-8+8>40+8

5x>48

Divide each side by 5

5x/5 >48/5

x > 9 3/5

Put them back together with the OR in the middle

x < -3/2 OR x > 9 3/5

kipiarov [429]2 years ago

6 0

Answer:

x < -1.5 U x > 9.6

Step-by-step explanation:

12x + 7 < -11

x < -1.5

5x - 8 > 40

5x > 48

x > 9.6

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denis-greek [22]

Answer:

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Step-by-step explanation:

Given equation of volume of cuboid is V= $2x^{3} +17x^{2} +46x+40$

Figure show that

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The volume of cuboid is given by

V=Length x Width x Height

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The volume of cuboid will be

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We get,

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