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iragen [17]
3 years ago
12

12x+7<−11 OR 5x−8>40 solve for x

Mathematics
2 answers:
Flura [38]3 years ago
7 0

Answer:

x < -3/2 OR x > 9  3/5

Step-by-step explanation:

12x+7<−11 OR 5x−8>40

Solve the inequalities separately

12x+7<−11

Subtract 7 from each side

12x+7-7<−11 -7

12x < -18

Divide each side by 12

12x/12 < -18/12

x < -3/2

Then solve the other inequality

5x−8>40

Add 8 to each side

5x-8+8>40+8

5x>48

Divide each side by 5

5x/5 >48/5

x > 9  3/5

Put them back together with the OR in the middle

x < -3/2 OR x > 9  3/5

kipiarov [429]3 years ago
6 0

Answer:

x < -1.5 U x > 9.6

Step-by-step explanation:

12x + 7 < -11

x < -1.5

5x - 8 > 40

5x > 48

x > 9.6

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Answer:

A, C, D and K

Step-by-step explanation:

First, plot the solution set to the system of two inequalities.

The inequality y\le -2x+10 determines solid line and bottom shaded region under this line.

The inequality y>\dfrac{1}{2}x-2 determines dotted line and top shaded region under this line.

The intersection of these two regions is the solution set to the system of two inequalities.

Points A, C, D and K belong to this region.

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No pie is left because 2/10 multiplied by 5 is 10/10, or 1 whole pie, so none of the pie is left.


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What are the coordinates of the point LaTeX: \frac{3}{4}\:3 4of the way from A to B? coordinate plane with line segment AB. Poin
egoroff_w [7]

Answer: \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

We need to find the coordinates of the point which is 3/4 of the way from A to B.

Let the required point be P.

AP:AB=3:4

AP:PB=AP:(AB-AP)=3:(4-1)=3:1

It means, point P divides segment AB in 3:1.

Section formula:  If a point divides a line segment in m:n, then

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Using section formula, we get

P=\left(\dfrac{3(-3)+1(-5)}{3+1},\dfrac{3(3)+1(-4)}{3+1}\right)

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Therefore, the required point is \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

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