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Salsk061 [2.6K]
4 years ago
8

Will mark BRAINLIEST

Mathematics
1 answer:
8_murik_8 [283]4 years ago
6 0
The solution is simply the point where the 2 graphs are intersecting and or touching each other at. In this case the solutions or the X coordinate of the points would be -1.7 and 4.
You might be interested in
Solve the system of linear equations.
icang [17]

Answer: The set does not have a solution

Step-by-step explanation:

Adding Equations 1 & 3 we get 5x = 7. This gives x = 7/5

Putting this value of x in eq. 2 we get

-2y + 2z = -1-(7/5) or

2y - 2z = 12/5  or  5y - 5z = 6

Multiplying eq. 1 by 2  we get  

4x + 2y - 2z = 6

adding this with eq. 2 we get 5x = 5 or x = 1

As the common solution for x from equations 1&3 does not satisfy eq. 1&2 it comes out that the three equations do not have a common solution.

Same can be verified by using different sets of two equations also.

7 0
4 years ago
3. Today, Dahlia folded 29 paper cranes. Now there are 41 paper cranes in class. How many cranes were there in class yesterday?
ohaa [14]

Answer:

There were 12 cranes in class yesterday. For all the cranes, there were a total of 290 centimeters.

Step-by-step explanation:

41-29=12.

29*10=290

4 0
2 years ago
What’s equivalent (2x^5)^3
Over [174]

Answer:

8x^15

Step-by-step explanation:

(2x5)3

=(2x5)3

=2x5*2x5*2x5

=8x15

6 0
3 years ago
line p contains points A(-7,-9) and B(4,0) line q is parallel to line p line r is perpendicular to line q what is the slope of l
igomit [66]
Use the slope formula (y2-y1)/(x2-x1)
(0+9)/(4+7)=9/11
Since q is parallel to r the slope will be the same. 9/11 is the slope of line r
4 0
4 years ago
100 Brainliest up for grabs to person who can answer all of these with no links:
kogti [31]

Using a discrete probability distribution, it is found that:

a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

c) The expected value is of 1.3 lawns mowed on a randomly selected day.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:

  • P(X = 0) = 0.2.
  • P(X = 1) = 0.4.
  • P(X = 2) = 0.3.
  • P(X = 3) = 0.1.

Item a:

P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

Item b:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2 = 0.8

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

Item c:

The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:

E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.

The expected value is of 1.3 lawns mowed on a randomly selected day.

More can be learned about discrete probability distributions at brainly.com/question/24855677

6 0
3 years ago
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