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2 years ago

Nick (austin?) spends $12 to buy 16 oranges how much dose Nick (austin?) spend per orange

Mathematics

2 answers:

iragen [17]2 years ago

5 0

Answer: $0.75

Step-by-step explanation:

$12 = 16 orange juice

which mean divide the money with the number of oranges to find how much nick spend per orange.

crimeas [40]2 years ago

3 0

Answer:

C. $1.33

Step-by-step explanation:

16 ÷ $12 = $1.33

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What is the hightest number that 9 and 27 both be divided into?

Elena L [17]

The highest number that both 9 and 27 can be multiplied into is 9. 9 can go into 9 one time, and 9 can go into 27 three times.
9•1=9
9•3=27
(9, 18, 27 )=times
I hope I helped.

3 0

3 years ago

Read 2 more answers

If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers

seraphim [82]

Answer:

a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

$\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}$

<h2>Simplify it in steps:</h2>

Bring both fractions into common denominator:

$\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}$

Simplify:

$\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =$

$\dfrac{4\sqrt{14} }{7-4} =$

$\dfrac{4}{3} \sqrt{14} }$

Compare the result with given expression to get:

a = 4/3 and b = 0

4 0

2 years ago

Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the

ANTONII [103]

Answer:

Length of right-angle triangle 'a' = 4

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

Step-by-step explanation:

Step(i):-

Given b = 3 and hypotenuse c = 5

Given ΔABC is a right angle triangle

By using pythagoras theorem

c² = a² + b²

⇒ a² = c² - b²

⇒ a² = 5²-3²

=25 - 9

a² = 16

⇒ a = √16 = 4

The sides of right angle triangle a = 4 ,b = 3 and c = 5

Step(ii):-

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

7 0

2 years ago

Collins is working.......

lesya [120]

Let n represent the amount Colin earned on Sunday.

On Sat. he earned n/2; on Sun. he earned n; and on Friday he earned (1/2)(n/2).

Then n/2 + n + n/4 = $70

Mult. all terms by 4 to eliminate fractions:

2n + 4n + n = $280

7n = $280 => n = $40

Colin earned n/2, or $20, on Saturday; n, or $40, on Sunday; and n/4, or $10, on Friday.

Note that $20 and $40 and $10 add up to $70, as they must.

4 0

3 years ago

Use substitution to solve the problem below algebraically. x = 41 x + 2y = 71

grandymaker [24]

Answer:

41 + 2y = 71

2y = 30

y = 15

Step-by-step explanation:

i believe that is right, if not sorry

7 0

3 years ago

Read 2 more answers