Answer:
24s^2, 54s^2, 96s^2
Step-by-step explanation:
Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).
a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),
b) tripled: A = 6(3s)^2 = 54x^2
c) quadrupled? A = 6(4s)^2 = 96s^2
Answer:
one
Step-by-step explanation:
i have no idea what kind of test ur taking my guy but have fun
Answer:
C
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the 2 other sides, that is
x² + 6² = 17²
x² + 36 = 289 ( subtract 36 from both sides )
x² = 253 ( take the square root of both sides )
x = 
→ C
Answer:
6 (may change if multiple number cubes are used; 2 dice = 6^2, 3=6^3, so on)
