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3 years ago

Can anybody please tell me the answers to these questions because I'm really confused

Mathematics

1 answer:

dimulka [17.4K]3 years ago

8 0

3. 3/10 and 5/10 4. 12/20 and 15/20 5.4/8 and 7/8 6. 8/12 and 5/12 7. 3/12 and 2/12. 8. 1/2>2/5 9.1/2 = 3/6 10. 3/4<5/6 11. 6/10=3/5

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Parallelogram ABCD is rotated to create image A'B'C'D'. On a coordinate plane, 2 parallelograms are shown. The first parallelogr

Gala2k [10]

Answer:

(x,y)→(y,-x)

Step-by-step explanation:

Parallelogram ABCD:

A(2,5)

B(5,4)

C(5,2)

D(2,3)

Parallelogram A'B'C'D':

A'(5,-4)

B'(4,-5)

C'(2,-5)

D'(3,-2)

Rule:

A(2,5)→A'(5,-2)

B(5,4)→B'(4,-5)

C(5,2)→C'(2,-5)

D(2,3)→D'(3,-2)

so the rule is

(x,y)→(y,-x)

4 0

3 years ago

Read 2 more answers

Pls help asappppppp it is very important I need it pls

Volgvan

Given:

The graph of a proportional relationship.

To find:

The constant of proportionality, the value of y when x is 24 and the value of x when y is 108.

Solution:

If y is directly proportional to x, then

$y\propto x$

$y=kx$ ...(i)

Where, k is the constant of proportionality.

The graph of proportional relationship passes through the point (5,15).

Substituting x=5 and y=15 in (i), we get

$15=k(5)$

$\dfrac{15}{5}=k$

$3=k$

Therefore, the constant of proportionality is 3.

Substituting k=3 in (i) to get the equation of the proportional relationship.

$y=3x$ ...(ii)

Substituting x=24 in (ii), we get

$y=3(24)$

$y=72$

Therefore, the value of y is 72 when x is 24.

Substituting y=108 in (ii), we get

$108=3x$

$\dfrac{108}{3}=y$

$36=y$

Therefore, the value of x is 36 when y is 108.

5 0

3 years ago

—330 + 450 need help !!!!!!!

natta225 [31]

120
hope that helps

7 0

3 years ago

Read 2 more answers

The height of Josie's dog is 11 1/4 inches to the nearest quarter inch and 11 inches to the nearest half inch. Which measurement

goldenfox [79]

Dear Kellyeasterday, 11 1/4 inches is more precise.

5 0

3 years ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

4 0

3 years ago