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3 years ago

If (n+1)!=90×(n-1)!,find n.

1 answer:

4 0

$\displaystyle\bf\\(n+1)!=90\times (n-1)!\\\\(n-1)!\times n\times(n+1)=90\times (n-1)!~~~\Big|~:(n-1)!\\\\n(n+1)=90\\\\n(n+1)=9\times10\\\\n(n+1)=9(9+1)\\\\\implies~~\boxed{\bf n=9}$

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Answer:

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Step-by-step explanation:

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3 years ago

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NikAS [45]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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Jobisdone [24]

Step-by-step explanation:

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3 years ago

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If (n+1)!=90×(n-1)!,find n.​

If (n+1)!=90×(n-1)!,find n.