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Elza [17]
3 years ago
12

Please help which system of inequalities is represented by the graph

Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0
Your anwser is c. Y>1 y-x>0
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Select the correct answer. What is the solution to the equation? 2(x+7)^2/3 = 8 A. -15 and 1 B. -15 C. 1 D. no solution
svet-max [94.6K]

Answer:

The answer has no solution because it is infinite and that's your vairiable

5 0
2 years ago
It takes a 2 1/2 yard from a bolt of fabric to make a costume for a school play. How much fabric would be needed for 8 costumes
Genrish500 [490]

Answer:

20 yards of fabric

Step-by-step explanation:

you can find this answer more easily by timing 2 by 8 then timing 1/2 by 8 witch would be 16 and 4 then all you do is add 16 and 4 to get 20

5 0
2 years ago
In one game, Jeremy’s quarterback had two touchdown passes,18 complete passes,6 incomplete passes, and 2 interceptions.How many
aliya0001 [1]

14 Points as one touchdown = 7 Points and he scored two so 14

3 0
3 years ago
Domain of function y=|x|​
Naddik [55]

Answer:

All real number

Step-by-step explanation:

The graph of y = x is shown to the right. We can see that it is defined for all x-values because the line will continue to infinity. Thus, the domain of y = x is all real numbers.

Hope this help <3

5 0
3 years ago
If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
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