Yes cause he can decrease the perimeter in any way and it would change the area and idk the other 2 in the front
Answer:
the first option
Step-by-step explanation:
variability !
what does that word tell us ?
it means that there are more individuals differences.
you could also use "accuracy" as the opposite - we are aiming for the mean value ...
imagine some bow and arrow tournament.
who wins ?
the person with the highest accuracy across all the attempts (and that means the lowest variability in the results across all attempts relatively to the target center representing the predefined mean value).
now look at the graphic for neighborhood A.
and then for neighborhood B.
which one has the data points more clustered around the center (where the mean value is going to be) ? this one has lower variability than the one where the data points are having more than one cluster or are even all over the place.
remember, for the variability you have to add all the differences to the mean value. the smaller the differences to the mean value, the smaller the variability.
in neighborhood B almost all data points have a larger difference to the mean value.
so, the variability will be higher here.
Answer:
D) 20 in
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h where r is the radius and h is the height
Substituting what we know
980 pi = pi (7)^2 h
Divide each side by pi
980 pi /pi= pi 49 h/pi
980 = 49h
Divide each side by 49
980/49 = 49h/49
20 =h
One scarf takes 3/5 of a yard. Two of these takes 6/5 of a yard. If we put the 1 7/10 into an improper fraction we would get 17/10. So in order to compare the two fractions, the 6/5 and the 17/10, they have to have the same denominator. 6/5 can be rewritten as 12/10. 12/10 is less that the 17/10 you have, so yes you can make two scarves with that amount of fabric.
Answer:
<h2>i) 3</h2><h2>ii) 5</h2>
Step-by-step explanation:
Let H be the set of students who play Hokey
V be the set of students who play Volleyball
S be the set of students who play Soccer
======================================
card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]
= 73 - [50 + (58-50) + (62-50)]
= 73 - [50 + 8 + 12]
= 73 - 70
= 3
………………………………………………
Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]
= 100 - 95
= 5
…………………
<u><em>Note</em></u> :
A Venn diagram might be helpful in such case.