Isnt it 16? Im pretty sure its 16 if not then idk lol
Think of A as a constant - with D it's 117 and with M it's 88
So the difference between D and M is 29 (117-88)
We also know that M + D = 161
Let's substitute in the problem We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.
M + M + 29 -161 or 2M +29 = 161 Subtracting 29 from both sides we get 2M=122
Now divide both sides two and get M=61
Since D is M+29 it is 61+29 or 100kg
Finally A + M = 88 A + 61 - 88 Subtract 61 from both sides and get A=17
So there you have it:
A=17kg
M=61kg
D=100kg and it works in all three equation in your problem (try it to check)
Answer:
Suppose that you have a square of side length x, the area of this square will be:
A = x^2.
Now, by dynamics, we know that the position of an object that is falling down from a height H, can be written as:
H(t) = (-g/2)*t^2 + H.
We can see a pattern, x^2 is used in both.
Now, profit can be also modeled with quadratic equations, where our objective is to find the maximum of the quadratic (so we can have the maximum profit)
Then the parent function that is useful for gravity, calculating area and profit is the quadratic function:
f(x) = x^2
As long as you believe in yourself, you can do anything.
Answer:
-8.05
Step-by-step explanation:
In order to solve for C you first have to subtract 17.6 from both sides.
2c=(6/4)-17.6
6/4 is 1.5
1.5-17.6=-16.1
2c=-16.1
c=-8.05
