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olchik [2.2K]
3 years ago
12

"From a standard deck of cards, find the number of different 5-card hands that are made up of 3 spades and 2 diamonds"

Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

^{13}C_3 \times ^{12}C_2 = 22308

Step-by-step explanation:

We have 5 spaces. In our hand.

_ _ _ _ _

a standard deck of 52 cards contains 13 cards for each suit.

so we have 13 spades and 13 diamonds in total. There arrangements don't matter (it doesn't matter if the first card is 9 of spades or the second is 9 of spades, all of these will be counted as one arrangement)

^{13}C_3: to choose the 3 spade card from a total of 13 spades.

^{12}C_2: to choose the 2 diamond cards from a total of 13 diamonds.

and that is it!

we're gonna multiply the two values.

^{13}C_3 \times ^{12}C_2

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Which does not describe the same situation y=3x+5
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Given the function. y = 3x + 5

For, x = -3; y = 3(-3) + 5 = -9 + 5 = -4
For x = 1; y = 3(1) + 5 = 3 + 5 = 8
For x = 4; y = 3(4) + 5 = 12 + 5 = 17

Thus the table representing the function is the table with: -3, 1 and 4 as x-values and -4, 8, 17 as y-values.

For x = 0; y = 3(0) + 5 = 0 + 5 = 5
For y = 0; 0 = 3x + 5; 3x = -5 and x = -5/3

Thus the graph of the function is a straight line passing through points (0, 5) and (-5/3, 0).

To illustrate the fuction as a word statement we say that y is five more than three times x


From the given descriptions, the graph does not represent the graph of y = 3x + 5.

Therefore, the one that does not describe the same situation is the graph.
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3 years ago
What is the approximate volume of this sphere?
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Answer: The correct answer is B. 523.3...cm^3

Step-by-step explanation:

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first, divide the diameter by 2 to get the radius, now, you will begin solving.

4/3*5^3*3.14

5*5*5=125

4/3*125*3.14

125*3.14=392.5

4/3*392.5

523.3...

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Step-by-step explanation:

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6

Step-by-step explanation:

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a(3) = \frac{3}{2}(-2)^{3-1}

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From point A, draw a line segment at an angle to the given line, and about the same length. The exact length is not important. Set the compasses on A, and set its width to a bit less than one fifth of the length of the new line. Step the compasses along the line, marking off 5 arcs. Label the last one C. With the compasses' width set to CB, draw an arc from A just below it. With the compasses' width set to AC, draw an arc from B crossing the one drawn in step 4. This intersection is point D. Draw a line from D to B. Using the same compasses' width as used to step along AC, step the compasses from D along DB making 4 new arcs across the line. Draw lines between the corresponding points along AC and DB. Done. The lines divide the given line segment AB in to 5 congruent parts.

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