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kvasek [131]
2 years ago
14

What kind of number is 0.87 rational or irrational

Mathematics
1 answer:
grigory [225]2 years ago
7 0

Answer: it is rational

Step-by-step explanation:

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Liam has 12 red balloons and 14 blue balloons. He puts all of his balloons in 2
777dan777 [17]

Answer:

I think it's 26. I think soooo

7 0
3 years ago
Which label on the cone below represents the center of the base?<br> D<br> B<br> Ο Α<br> OB
Firlakuza [10]

Answer:

C

Step-by-step explanation:

The center of the base is the center of the circle

The center of the circle is C

8 0
2 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
2 years ago
Help me with this math problem.
kherson [118]

Answer:

158.333333

Step-by-step explanation:

do the percent correct divided by the number of questions then multiply it by 100

95/60=1.58333333

1.58333333*100=158.333333

8 0
3 years ago
Which is a complete list of factors of each term in the expression 16a+18ab?
gregori [183]

Answer:

2a

Step-by-step explanation:

2a(8+9b)

Open the bracket you have

16a+18ab

4 0
3 years ago
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