Please help mePlease do step by step. Thanks

Mathematics

2 answers:

lianna [129]3 years ago

7 0

5^3 = 5*5*5 = 125
125 -12 = 113
113 / 3 = 37.6666666

ddd [48]3 years ago

3 0

5*5*5 - 12/3 first multiply 5*5*5
125 - 4 Then divide 12 by 3
= 121 Then subtract 125 by 4
You get 121 as your answer
Hope this helped you!

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What is the estimated margin of error, using standard deviation?

OLEGan [10]

Find the mean ( average):
105 + 104 + 110 + 112 + 114 + 106 + 108 +109 = 868
Mean = 868 / 8 = 108.5

Standard deviation:
108.5 - 105 = 3.5, 3.5^2 = 12.25
108.5 - 104 = 4, 4^2 = 16
110 - 108.5 = 1.5, 1.5^2 = 2.25
112 - 108.5 = 3.5, 3.5^2 = 12.25
114 - 108.5 = 5.5, 5.5^2 = 30.25
108.5 - 106 = 2.5, 2.5^2 = 6.25
108.5 - 108 = 0.5, 0.5^2 = 0.25
109 - 108.5 = 0.5, 0.5^2 = 0.25

12.25 + 16 +2.25 + 12.25 + 30.25 +6.25+0.25+0.25 = 79.75
79.75/8 = 9.96875, SQRT(9.96875) = 3.1573

Standard Deviation = 3.1573

108.8 +/- 1.96 *(3.1573/sqrt(8) = 110.687 and 106.312

110.687 - 108.5 = 2.19
108.5 - 106.312 = 2.19

Margin of error = +/- 2.19

3 0

3 years ago

HELP ASAP!! Identify the matrix transformation of ΔPQR, which has coordinates P(−5, −2),Q(−6, −3), and R(−2, −3), for reflection

podryga [215]

Answer:

Matrix transformation = $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ .

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-5\\-2\end{array}\right]$ = (5,-2)