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Anna007 [38]
3 years ago
6

Robin purchased 3 1\2 ounces of whole wheat cereal for $1.40. What is the cost per ounce?

Mathematics
1 answer:
Natalka [10]3 years ago
8 0
The answer is 40 cents
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Is xy=yx distributive property
Molodets [167]
No, xy = yx is not distributive property, Hope this helps
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Find the equation of circle (5,1) diameter 4 square root 5​
stepladder [879]

Answer:

(x-5)^2+(y-1)^2=20

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

(where (a, b) is the center and r is the radius)

Given:

  • center = (5, 1)
  • diameter = 4√5

Diameter = 2r (where r is the radius)

⇒ r = 4√5 ÷ 2 = 2√5

Substituting these values into the equation:

\implies (x-5)^2+(y-1)^2=(2\sqrt{5})^2

\implies (x-5)^2+(y-1)^2=20

6 0
2 years ago
X - (2x + 1) = 8 - (3x + 2)
vlada-n [284]

Answer:

x=7/2

Step-by-step explanation:

7 0
3 years ago
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What is the quotient of 13 divided by 8
Masteriza [31]
1.625 or/and 13/8 should be your answer
8 0
2 years ago
WHO CAN solve it Please !
Mariulka [41]

Answer:

a) True

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the definite integration</em>

<em>            </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha<em></em>

<em>we know that the trigonometric formula</em>

<em> sin²∝+cos²∝ = 1</em>

<em>            cos²∝ = 1-sin²∝</em>

<u><em>step(ii):-</em></u>

<em>Now the  integration</em>

<em>         </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha<em></em>

<em>                                      = </em>\int\limits^\pi _0 {cos\alpha } \, dx<em></em>

<em>Now, Integrating </em>

<em>                                  </em>= ( sin\alpha )_{0} ^{\pi }<em></em>

<em>                                = sin π - sin 0</em>

<em>                               = 0-0</em>

<em>                              = 0</em>

<u><em>Final answer:-</em></u>

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

<em></em>

<em></em>

5 0
3 years ago
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