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Lina20 [59]
3 years ago
14

Factor 5k 2 - 35k 3. A. 5k2(1 - 7k) B. 5k3(1 - 7k) C. 5k(1 - 7k2)

Mathematics
2 answers:
solniwko [45]3 years ago
4 0

Answer:

The correct answer is A) 5k^2(1 - 7k)

Step-by-step explanation:

To factor, take out the greatest common multiple. Each term has a factor of 5 that can be taken out as a constant and k^2 as a variable. Take both of these out and divide each term by that expression.

5k^2(1 - 7k)

Elanso [62]3 years ago
4 0

its A) 5k^2(1 - 7k) :)

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aalyn [17]

Answer:

17x +215/ 5

Step-by-step explanation:

17x +215

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3 0
3 years ago
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Y=2(x+1)^2 has how many real roots
oee [108]

The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

=> y = 2(x+1)^2

Take y=0 then,

=> 2(x+1)^2=0

=> (x+1)^2=0

=>(x+1)=0

=> x=-1

Hence the given equation has one real root and that is x=-1.

To learn more about real roots refer the below link

brainly.com/question/24147137

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1 year ago
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8 0
3 years ago
Does 32.60 round up or round down
adelina 88 [10]

That all depends what place you want it rounded to.

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3 0
3 years ago
Show that in any group of 101 people there are at least two persons having the same number friends (It is assumed that if a pers
vladimir1956 [14]

Answer:

Step-by-step explanation:

Let us assume that if possible in the group of 101, each had a different number of friends.  Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.

Say P has 100 friends then P has all other persons as friends.  In this case, there cannot be any one who has 0 friend.  So a contradiction.  Hence proved

Part ii: EVen if instead of 101, say n people are there same proof follows as

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If one person has n-1 friends then there cannot be any one who does not have any friend.

Thus same proof follows.

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3 years ago
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