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Alecsey [184]
2 years ago
7

How do I solve this problem about reflection?

Mathematics
1 answer:
marishachu [46]2 years ago
4 0
F should be -1, 6
E should be -4, 2
D should be -4, 9
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Suppose y varies directly with x. If y = –20 when x = 2, find y when x = 14
Natasha_Volkova [10]

Answer:

y = -140

Step-by-step explanation:

Y varies directly with x

y = kx

We know y = -20 when x =2, we can solve for k

-20 = k*2

Divide each side by 2

-20/2= 2k/2

-10 =k

y = -10x

Now we want to find y when x = 14

y = -10 *14

y = -140

3 0
3 years ago
Read 2 more answers
Samantha has some dimes and quarters. She has 7 more dimes than quarters and the collection of coins is worth $10.15. How many d
Umnica [9.8K]
Omg my name is Samantha sorry i can’t help you. I hope someone can help you!!!!
6 0
2 years ago
Which statement about an extraneous solution is not correct? Select all that apply.
horsena [70]

Answer:

It comes from correct solution steps and is not a valid solution of the equation.

Step-by-step explanation:

8 0
2 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
Hey! Last day for me to do Algebra before exams so this is an emergency!! Help would definitely be appreciated and do NOT answer
il63 [147K]

Part 1 -

1. f(x) = 5(x-2)^2 + 4

axis of symmetry: x = 2

vertex: (2, 4)

2. f(x) = 12(x + 6)^2 - 5

axis of symmetry: x = -6

vertex:  (-6, -5)

3. f(x) = 2x^2 + 8x - 7

axis of symmetry: x = -2

vertex: (-2, -15)

I have to go somewhere right now, but I will get back to you as soon as I can (probably within a couple of hours) to finish answering the rest of your questions.


4 0
2 years ago
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