A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% o
f the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?
1 answer:
(4/10)(5/100)=20/1000
1/50
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1hr25m+45m=2hr10min
125+45=170
D.) 170min
All you had to do was add both of the numbers together.