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2 years ago

Simplify x + x + y y

Mathematics

1 answer:

kolezko [41]2 years ago

4 0

Answer:

2x+2y

Step-by-step explanation:

x+x = 2x

y+y = 2y

2x+2y

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Pls help<br><br>linear equations<br>

NeTakaya

Answer:

I don’t think nobody can help you here because the picture doesn’t show up, sorry

7 0

2 years ago

Read 2 more answers

Identifying the equivalent expression

iragen [17]

Answer:

$\large\boxed{\sqrt{x+3}=(x+3)^\frac{1}{2}}$

Step-by-step explanation:

$\text{Use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\sqrt{x+3}=\sqrt[2]{x+3}=(x+3)^\frac{1}{2}$

6 0

2 years ago

What’s the area of a rectangle measuring 13 inches times 12 inches ?

taurus [48]

Answer:

156 square inches

Step-by-step explanation:

We are given the two quantities

Let

length = l = 13 inches

and

Width = w = 12 inches

The formula for the area of rectangle is:

$Area=l*w$

where l is length and w is width

Putting the values of both that are given

$Area = 13*12\\=156$

so the area is 156 square inches ..

6 0

2 years ago

Find the distance between the points. (Round your answer to two decimal places. (9.7, - 2.8), (- 3.2, 8.8)

Dmitry [639]

Answer:

Rounding it to two decimal places, we get distance, $d=17.35$

Step-by-step explanation:

Given:

The two points are $(9.7, -2.8)\textrm{ and }(-3.2, 8.8)$

The distance between the two points can be obtained using the distance formula which is given as:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Here, for the points, $(9.7, -2.8)\textrm{ and }(-3.2, 8.8)$

$x_{1}=9.7,x_{2}=-3.2,y_{1}=-2.8,y_{2}=8.8$

Therefore, the distance between the points is:

$d=\sqrt{(-3.2-9.7)^2+(8.8-(-2.8))^2}\\d=\sqrt{(-12.9)^2+(8.8+2.8)^2}\\d=\sqrt{(12.9)^2+(11.6)^2}\\d=\sqrt{166.41+134.56}\\d=\sqrt{300.97}=17.348$

Rounding it to two decimal places, we get $d=17.35$

7 0

2 years ago

A line intersects the point (-11, 4) and has a slope of -2. What are the inputs to the point-slope formula? y - [?] = [](x-[])

Lyrx [107]

y - 4 = -2 ( x - ( -11)) which would simplify to y - 4 = -2 ( x + 11) !!

5 0

2 years ago